# Where to watch Sandy Wexler (2017) in the UK

> Sandy Wexler (2017) is currently available to stream in the UK on Netflix and Netflix Standard with Ads. Last verified on 5 May 2026 by ScreenSearch.

**Type:** Film  
**Year:** 2017  
**Runtime:** 130 minutes  
**TMDB rating:** 5.5/10  
**Genres:** Comedy, Drama, Romance  
**Region:** United Kingdom (GB)  
**Last verified:** 5 May 2026 (2026-05-05T22:52:19.726Z)  

## Synopsis

When a hapless but dedicated talent manager signs his first client who actually has talent, his career finally starts to take off.

## Streaming options in the United Kingdom

### Stream (subscription)

- [Netflix](https://www.netflix.com/search?q=Sandy%20Wexler)
- [Netflix Standard with Ads](https://www.netflix.com/search?q=Sandy%20Wexler)

## Frequently asked questions

**Where can I stream Sandy Wexler in the UK?**

Sandy Wexler (2017) is currently included in subscriptions to Netflix and Netflix Standard with Ads in the United Kingdom. Sign-in is required to play. Streaming licences change occasionally — ScreenSearch refreshes its data daily.

**Is Sandy Wexler on Netflix, Disney+ or Amazon Prime Video in the UK?**

Sandy Wexler is currently included with: Netflix and Netflix Standard with Ads.

**How accurate is this film's availability data?**

Availability is sourced from The Movie Database (TMDB), which in turn pulls from JustWatch. Listings are refreshed daily. For purchase decisions, the provider's own site is the source of truth.

## Sources

- Streaming availability: The Movie Database (TMDB), refreshed daily.
- Underlying licensing data: JustWatch.
- Canonical URL: https://www.screensearch.co.uk/watch/movie/419700/sandy-wexler-2017
- Poster image: https://image.tmdb.org/t/p/w500/38SDqWOt4utiLOnWlas7BfrYQGS.jpg
- JSON variant: https://www.screensearch.co.uk/watch/movie/419700/sandy-wexler-2017.json

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Generated by [ScreenSearch](https://www.screensearch.co.uk/) — a free UK-focused tool that answers "where can I watch this in the UK?" for any film or TV show. No accounts, no signup.